Q. A photon traveling in the positive x-direction collides with a stationary free electron. The incident photon has a wavelength of 0.0310 nm. Post-collision, the electron moves at an angle 𝛼 below the positive x-axis, and the photon deflects at an angle 𝜃 = 66.3° above the positive x-axis. A) Calculate the angle 𝛼 (in degrees). B) Compute the velocity of the electron (in m/s). Solution:
Motion in Plane: Previously we discussed motion in a straight line. Motion in straight line belongs to one dimension. Thus, Motion in plane defined in two dimensions. If an object is free to move in a plane, its position can be located with two co-ordinates. Let's consider an object is situated in x-y plane. It moves along the following path- During the path object moves along X direction as well as Y direction. In time interval t to t+t 1 (here t 1 is very small time interval) object displaced x 1 and y 1 in X and Y direction respectively . Displacement is in both X and Y direction, so there will be different velocity and acceleration in both directions. If we take u x ,v x ,a x as initial velocity ,final velocity and acceleration in X direction and u y ,v y ,a y as initial velocity ,final velocity and acceleration in Y direction. Consider both the accelerations constant. In time t object have 'x' and 'y' displacements along X-axes and Y-axes respective